10x^2-1400=0

Solution for 10x^2-1400=0 equation:

10x^2-1400=0

a = 10; b = 0; c = -1400;
Δ = b2-4ac
Δ = 02-4·10·(-1400)
Δ = 56000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{56000}=\sqrt{1600*35}=\sqrt{1600}*\sqrt{35}=40\sqrt{35}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{35}}{2*10}=\frac{0-40\sqrt{35}}{20}
=-\frac{40\sqrt{35}}{20}
=-2\sqrt{35}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{35}}{2*10}=\frac{0+40\sqrt{35}}{20}
=\frac{40\sqrt{35}}{20}
=2\sqrt{35}
$